Prove that the lengths of tangents drawn from an external point to a circle are equal.

Given: PT and PS are tangents from an external point P to the circle with center O.
To prove:
PT = PS
Construction: Join O to P, T, and S
Proof:
In ΔOTP and ΔOSP,
OT=OS …[radii of same circle
OP=OP …[Common
∠OTP=∠OSP …[Each 90o
∴ ΔOTP≅ΔOSP …[R.H.S.
Hence, PT =PS …[c.p.c.t.
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