Solve the following system of equations:
=
=
⇒
8(x+y-8) = 2(x+2y-14)
6x + 4y - 36 = 0
3x + 2y - 18 = 0 … (i)
⇒
11(x + 2y -14) = 8(3x + y - 12)
13x - 14y + 58 = 0 … (ii)
Multiplying (i) by 7 and subtracting from (ii),
34x - 68 = 0 or x = 2
Substituting x = 2 in (i),
3(2) + 2 y - 18 = 0
6 + 2y -18 = 0
2y -12 = 0
y = 6
The solution set is {2, 6}.
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