Determine graphically, the vertices of the triangle, the equations of whosesides are given below:
2x – y + 1 = 0, x – 5y + 14 = 0 and x – 2y + 8 = 0.
2x – y + 1 = 0
y = 2x + 1
| x | 0 | 1 | 2 |
| y = 2x + 1 | 1 | 3 | 5 |
x – 5y + 14 = 0
⇒ 5y = x + 14
∴ y =
| X | 1 | -4 | 6 |
| y = | 3 | 2 | 4 |
x – 2y + 8 = 0
⇒ 2y = x + 8
∴ y =
| X | 0 | 2 | - 2 |
| y = | 4 | 5 | 3 |
The vertices of the triangle formed by the three lines are (2, 5), (1, 3) and (- 4, 2).
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