Q24 of 35 Page 3


Find three consecutive numbers such that seven times the smallest number may beequal to three times the sum of the other two.


Let the smallest number = x.
Then the other two numbers are x + 1 and x + 2.
Also 7 times smallest number = 7x.
3 times the sums of other two numbers = 3(x + 1 + x + 2).
According to the condition of the problem
7x = 3(x + 1+ x + 2) or 7x = 6x + 9
x = 9
Hence the numbers are 9, 10, 11.

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