Find the sum and product of the zeroes of the polynomial x 2â25.
Let P(x) = x 2 - 25
If a x 2 + bo x + c is the polynomial, then
Sum of the zeroes of the polynomial = -( b/a )
The product of the zeroes of the polynomial = ( c/a )
Here, a = 1, b = 0, c = -25
â´ Sum of zeroes of the given polynomial = -(0/1) = 0
Product of zeroes of the given polynomial = (-25/1) = - 25.
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