Q35 of 69 Page 65

If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

Given:

Diameter of carbon atom = 0.15 nm


Radius of carbon atom = [0.15 / 2] = 0.075 nm


Length of line = 20 cm


Number of carbon atoms which can be place along the line is given by n = [20× 10-2] / [0.15× 10-9]


n = 1.333× 109


Therefore, the number of carbon atoms which can be place along the line is 1.333× 109.


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