The bromine atom possesses 35 electrons. It contains 6 electrons in 2p orbital, 6 electrons in 3p orbital and 5 electron in 4p orbital. Which of these electron experiences the lowest effective nuclear charge?

If the position of the electron is measured within an accuracy of + 0.002 nm, calculate the uncertainty in the momentum of the electron. Suppose the momentum of the electron is , is there any problem in defining this value.

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has/have the same energy lists:

1. n = 4, l = 2, m_l= –2 , m_s = –1/2

2. n = 3, l = 2, m_l= 1 , m_s = +1/2

3. n = 4, l = 1, m_l= 0 , m_s = +1/2

4. n = 3, l = 2, m_l= –2 , m_s = –1/2

5. n = 3, l = 1, m_l= –1 , m_s = +1/2

6. n = 4, l = 1, m_l= 0 , m_s = +1/2

Among the following pairs of orbitals which orbital will experience the larger effective nuclear charge?

(i) 2s and 3s

(ii) 4d and 4f

(iii) 3d and 3p

The unpaired electrons in Al and Si are present in 3p orbital. Which electrons will experience more effective nuclear charge from the nucleus?