Skip to content
Philoid
Browse Saved
Back to chapter
Chemistry
2. Structure of Atom
Home · Class 11 · Chemistry · Chemistry Part-I · 2. Structure of Atom
Prev
Next
Q36 of 69 Page 65

2 ×108 atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

Given:

Number of carbon atoms, n = 2 ×108


Length of the arrangement, l = 2.4 cm


Number of carbon atoms which can be place along the line is given by n = [l] / [diameter, d]


D= [l] / [n]


D = [2.4× 10-2] / [2 ×108]


D = 1.2× 10-10 m


Therefore radius = [1.2× 10-10] / 2


= 0.6× 10-10 m


Therefore, the radius of carbon atom is 0.6 Å.


More from this chapter

All 69 →
34

Calculate the energy required for the process


The ionization energy for the H atom in the ground state is 2.18 × 10–18 J atom–1

35

If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

37

The diameter of zinc atom is 2.6 Å. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

38

A certain particle carries 2.5 × 10–16C of static electric charge. Calculate the number of electrons present in it.

Questions · 69
2. Structure of Atom
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 23 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67
Back to chapter
About Contact Privacy Terms
Philoid · 2026
  • Home
  • Search
  • Browse
  • Quiz
  • Saved