If the sum of n terms of two arithmetic progressions are in the ratio 5n + 4 : 9n + 6, find the ratio of their 18th terms.
If the sum of n terms of two arithmetic progressions are in the ratio 5n + 4 : 9n + 6, find the ratio of their 18th terms.
For first A.P. :
Let first term = a1
Common difference = d1
and Sn1 = Sum of n terms
For second A.P. :
Let first term = a2
Common difference = d2
and Sn2 = Sum of n terms
Given
=
Required to find
=
We have
=
or
=
or
=
Taking
= 17 or n = 34 + 1 = 35, we have
=
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