Sums of the first p, q, r terms of an A.P are a, b, c respectively. Prove that
Sums of the first p, q, r terms of an A.P are a, b, c respectively. Prove that
Let x be the first term and d the common difference.
Sp = p/2[ 2x + (p-1)d] = a
Sq = q/2[2x + (q-1)d] = b
Sr = r/2[2x + (r-1)d] = c
2x + (p-1)d = 2a/p………..(i)
2x + (q-1)d = 2b/q………..(ii)
2x + (r-1)d = 2c/r………….(iii)
Eliminating x and d from (i), (ii) and (iii).
(p-q)d = 2a/p - 2b/q [Subtracting (i) and (ii)] ……(iv)
(q-r)d = 2a/q - 2c/r [Subtracting (iii) and (ii)] … (v)
[ Dividing (iv) and (v)]
=
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