Q4 of 47 Page 1

If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible values of k?


Given: Distance between A and B = 5 units.


If A(x1, y1) and B(x2, y2) be two points, then the distance between points is given by:


(AB)2 = (x2 - x1)2 + (y2 - y1)2


⇒ (5)2 = (1 - 4)2 + (0 – k)2


⇒ 25 = (-3)2 + (-k)2


⇒ 25 = 9 + k2


⇒ k2 = 25 – 9


⇒ k2 = 16


⇒ k = √16


⇒ k = 4


Therefore, possible values for k are 4 and -4.


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