Q17 of 47 Page 1

Show that Δ ABC, where A(–2, 0), B(2, 0), C(0, 2) and Δ PQR where P(–4, 0), Q(4, 0), R(0, 4) are similar triangles.

Vertices of ΔABC are A(-2, 0), B(2, 0) and C(0, 2).

AB =


BC =


CA =


Vertices of ΔPQR are P(-4, 0), B(4, 0) and C(0, 4).


PQ =


QR =


RP =


Now,


AB/PQ = 4/8 = 1/2


BC/QR = 2√2/4√2 = 1/2


CA/RP = 2√2/4√2 = 1/2


Since the corresponding sides of both the sides are proportional, therefore both the triangles are similar.


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