Q28 of 47 Page 1

Draw a right triangle in which the sides (other than the hypotenuse) are of lengths 4 cm and 3 cm. Now construct another triangle whose sides are 3/5 times the corresponding sides of the given triangle.

Construction Steps:

Step 1: Draw BC = 4 cm.


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Step 2: At point B, draw AB = 3 cm making a right angle at ∠ABC with BC.


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Step 3: Join AC to form ΔABC.


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Step 4: Draw any ray BX making an acute angle with BC on the side opposite to the vertex A.


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Step 5: Locate 5 points B1, B2, B3, B4 and B5 on BX so that BB1 = B1 B2 = B2 B3 = B3 B4 = B4 B5.


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Step 6: Join B5C and draw a line through B3 || B5C to intersect BC at C′.


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Step 7: Draw a line through C′ parallel to the line CA to intersect BA at A.


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Thus, ΔA’BC’ is the required triangle.


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