The radii of ends of a frustum are 14 cm and 6 cm respectively and its height is 6 cm. Find its

i) Curved surface area

ii) Total surface area

iii) Volume

(i) The two radii of frustum are, r₁ = 14cm and r₂= 6cm

Height of frustum, H = 6cm

Slant height of frustum,

⇒ l = 10

As we know that,

Curved surface area, A_C = πl(r₁ + r₂)

⇒ A_C = (3.14) × 10 × (14 + 6)

⇒ A_C = (3.14) × 200

⇒ A_C = 628 sq. cm

∴ the curved surface area of frustum is 628 sq. cm

(ii) Total surface area, A_T = Curved surface area + area of the two circular regions

A_T = A_C + πr₁² + πr₂²

On substituting the above values, we get,

⇒ A_T = 628 + (3.14) × (14² + 6²)

⇒ A_T = 628 + (3.14)× (196 + 36)

⇒ A_T = 628 + 728.48

⇒ A_T = 1356.48 sq. cm

∴ the total surface area of frustum is 1356.48 cm²

(iii) As we know,

On substituting the values, we get,

V = 1984.48 cm³

∴ Volume of the frustum is 1984.48 cm³