Q6 of 52 Page 154

In the figure 7.31, radius of the circle is 7 cm and m(arc MBN) = 60°,find


(1) Area of circle


(2) A(O – MBN)


(3) A(O - MCN)

(1) Radius of circle, r = 7cm

Area of circle,AC = πr2



⇒ AC = 154 sq. cm


∴ area of circle is 154 sq.cm


(2) Angle subtended by the arc = 60°


As we know,





⇒ A(O- MBN) = 25.7 sq. cm


(3) A(O- MCN) = Area of circle – A(O – MBN)


⇒ Area(O – MCN) = AC – 25.7


⇒ Area(O – MCN) = 154 – 25.7


∴ Area of major sector is 128.3 sq. cm


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