In the figure 7.45, if A is the centre of the circle. ∠ PAR = 30°, AP = 7.5, find the area of the segment PQR. (π = 3.14)

Radius of circle, r = 7.5 cm
∠ PAR = θ = 30°
Area(A – PQR), AS:
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⇒ AS = 14.71 sq.cm
Also,
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⇒ AT = 14.06 sq. cm
Area of segment PQR, AR = AS - AT
⇒ AR = 14.71 – 14.06 = 0.6562 sq.cm
∴ Area of shaded region is 0.6562 sq.cm
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