In the given figure, ABCD and BCDE are parallelograms with common base DC. If BC
BD, then ∠BEC=

∠ BAC = 300 (Given)
∠ ABC = 1500(Supplementary angles)
∠ ABD = 1500-900 = 600
∠ BDC = 600(Co interior angles)
∠ BEC = 600(Opposite angles)
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