Q157 of 160 Page 144

In the following figure of a ship. ABDH and CEFG are two parallelograms. Find the value of x.

In llgm ABDH,

D = BAH = 180-130(adjacent angles)


In llgm CEFG,


C = GCE = GFE = 30(opposite angles)


Hence, in ∆CDX,


C + D + x = 180


30 + 130 + x = 180


x = 180-160 = 20


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