In the following figure of a ship. ABDH and CEFG are two parallelograms. Find the value of x.

⟹In llgm ABDH,
∠D = ∠BAH = 180-130(adjacent angles)
⟹In llgm CEFG,
∠C = ∠GCE = ∠GFE = 30(opposite angles)
⟹Hence, in ∆CDX,
∠C + ∠D + ∠x = 180
30 + 130 + ∠x = 180
∠x = 180-160 = 20
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