Q49 of 160 Page 144

The number of sides of a regular polygon who’s each interior angle is of 135° is

Each interior angle = 135⁰

Let the number of sides be n

Sum of interior angles = n×135⁰

Sum of interior angles is given by = (2n-4) × 90⁰

Equating we get

(2n-4)90 = 135n

⇒ 180n-360 = 135n

⇒ 45n = 360

⇒ n = 8

The angles P, Q, R and S of a quadrilateral are in the ratio 1:3:7:9. Then PQRS is a

PQRS is a trapezium in which PQSR and P = 130°, Q = 110°, then R is equal to :

If a diagonal of a quadrilateral bisects both the angles, then it is a

To construct a unique parallelogram, the minimum number of measurements required is