In a rectangle ABCD. AB = 25cm and BC = 15cm. In what ration does the bisector of
C divides AB?
The figure is given below:

Given, a rectangle ABCD
AB = 25cm
BC = 15cm
Bisector of ∠C divides AB i.e. ∠BCE = 45
⟹ By angle sum property of triangle.
∠BEC = 45
⟹ BC = BE, because sides having equal angles are equal.
BE = 15cm
And AE = AB-BE = 25-15
AE = 10cm
AE:BE = 10:15
AE:BE = 2:3
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