Q2 of 54 Page 308

A die is thrown twice. Find the probability of getting a total of 9.

The outcomes on throwing a dice twice are: (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)


(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)


(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)


(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)


(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)


(61),(6,2),(63),(6,4),(6,6),(6,6)


Thus the total probable outcomes = 4


⇒ probability



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