If A and B are mutually exclusive events and S is the sample space such that

and S = A ∪ B, then P (A) =

If A and B are two events such that

P (A) = 0.25, P (B) = 0.05 and P(A ∩ B) = 0.14, then P(A ∪ B) =

There are 6 defective items in a sample of 20 items. One item is drawn at random. The probability that it is a non-defective item is

The probabilities of three mutually exclusive events A, B and C are given by and. Then P(A ∪ B ∪ C) is

If P(A) = 0.25, P (B) = 0.50, P(A ∩ B) = 0.14 then P (neither A nor B) =