The probability that A, B and C can solve a problem are
and
respectively. The probability of the problem being solved by A and B is
, B and C is
, A and C is
. The probability of the problem being solved by all the three is
. Find the probability that the problem can be solved by atleast one of them.
Given:
P(A)![]()
P(B)![]()
P(C)![]()
P(A ∩B)
P(B ∩C)
P(A ∩C)
P(A ∩B ∩C)
Thus
P(AUBUC) = P(A)+P(B)+P(C)+ P(A ∩B)+ P(C ∩B)+ P(A ∩C)- P(A ∩B ∩C)
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