If a die is rolled twice, find the probability of getting an even number in the first time or a total of 8.
The outcomes on throwing a dice twice are: (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(61),(6,2),(63),(6,4),(6,6),(6,6)
Total outcomes = 36
Probable outcome that the even number in the first time or a total of 8.
comes = 20
⇒ probability ![]()
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