Q13 of 164 Page 41

Evaluate.

(i) sin 45° + cos 45°


(ii) sin 60° tan 30°


(iii)


(iv) cos260° sin230° + tan2 30° cot2 60°


(v) 6cos2 90° + 3sin2 90° + 4 tan2 45°


(vi)


(vii)


(viii) 4(sin4 30° + cos4 60°) – 3 (cos2 45° – sin2 90°)


(i) We know sin 45° = (1/√2) and cos 45° = (1/√2) (From the table)




(ii) We know sin 30° = 1/2 and tan 45° = 1 (From the table)



(iii) We know tan 30° = (1/√3) (From the table)


tan 45° = 1


tan 60° = √3





(iv) We know sin 30° = cos 60° = 1/2 (From the table)


tan 30° = cot 60° = 1/√3






(v) We know that cos 90° = 0 , sin 90° = 1 and tan 45° = 1 (From the table)


6(0)2 + 3(1)2 + 4(1)2


3 + 4


7


(vi) We know cot 60° = (1/√3) (From the table)


sec 30° = 2/√3


sin 45° = 1/√2


sin 60° = √3/2


cos 45° = 1/√2






(vii) We know tan 60° = √3 (From the table)


cos 45° = 1/√2


sec 30° = 2/√3


cos 90° = 0


cosec 30° = 2


sec 60° = 2


cot 30° = √3




9


(viii) We know


sin 30° = cos 60° = 1/2 (From the table)


cos 45° = 1/√2


sin 90° = 1


4(


4(


4(


2


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