Find the value of the following.

tan 10^o 26’

We write tan 10° 26’ = tan 10° 24’ + 2’.

The relevant part of the tangent table is given below.

From the table, we have

tan 10° 24’ = 0.1835

Mean difference for 2’ = 0.0006

We know that mean difference is to be added in the case of tangent.

∴ tan 10° 26’ = 0.1835 + 0.0006 = 0.1841