In the figure at right, AB and CD are two parallel chords of a circle with centre O and radius 5 cm such that AB = 6 cm and CD = 8 cm. If OP ⊥ AB and CD ⊥ OQ determine the length of PQ.

From Theorem: A circle with radius r and a chord of length l which is at distance d from the centre, follows the equation,
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For Triangle COQ
OC = 5cm ,
CQ = half of chord length = 4cm
From Pythagoras theorem
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OQ = 3cm
For triangle POA
OA = 5cm, AP = half of chord length = 3cm
From Pythagoras theorem
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OP = 4cm
From figure PQ = OP – OQ
Therefore PQ = 1cm
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