Q13 of 29 Page 61

In the figure at left ,ABCD is a cyclic quadrilateral in which AB || DC. If BAD = 100°

find (i) BCD (ii) ADC (iii) ABC.


As ABCD is a cyclic quadrilaterals, sum of all angles = 360°

As AB is parallel to CD


ADC = 180 – DAB = 80° as they are interior angles on the same side.


As angle subtended by chord BD on circumference = 100°


Therefore BCD = 100°


As BCD and ABC are interior angles


ABC = 180 – BCD = 80°


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