In the figure at left ,ABCD is a cyclic quadrilateral in which AB || DC. If ∠BAD = 100°
find (i) ∠BCD (ii) ∠ADC (iii) ∠ABC.

As ABCD is a cyclic quadrilaterals, sum of all angles = 360°
As AB is parallel to CD
∠ADC = 180 – ∠DAB = 80° as they are interior angles on the same side.
As angle subtended by chord BD on circumference = 100°
Therefore ∠BCD = 100°
As ∠BCD and ∠ABC are interior angles
∠ABC = 180 – ∠BCD = 80°
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