In the figure at right, AB and CD are two parallel chords of a circle with centre O and radius 5 cm. Such that AB = 8 cm and CD = 6 cm. If OP ⊥ AB and OQ ⊥ CD determine the length PQ.

From Theorem: A circle with radius r and a chord of length l which is at distance d from the centre, follows the equation,
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In triangle APO
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OP = 3cm.
In triangle COQ
![]()
OQ = 4cm
From figure PQ = OP + OQ = 7cm.
Hence PQ = 7cm.
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