In the figure at left, O is the centre of the circle, ∠AOC = 100° and side AB is produced to D.
Find (i) ∠CBD (ii) ∠ABC

As the angle subtended by chord AC on center O is 100°.
Angle subtended by chord AC on major segment = 50°
As the sum of angle subtended by chord AC on major and minor segments is 180°
Hence ∠ABC = 180–50 = 130°
As line AD is straight
Hence ∠CBD = 180 – 130 = 50°
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.



