Q12 of 29 Page 61

In the figure at right, ABCD is a cyclic quadrilateral whose diagonals intersect at P such that DBC = 30°and BAC = 50°.

Find (i) BCD (ii) CAD


As ABCD is a cyclic quadrilaterals, sum of all angles = 360°


As the angle subtended by chord BC on circumference = 50°


Therefore BDC = 50°


Sum of all angles of triangle BCD = 180°


Hence BCD = 180– 30–50 = 100°


As the angle subtended by chord DC on circumference = 30°


Therefore CAD = 50°


More from this chapter

All 29 →