If 2x = 16, find
i. x
ii. ![]()
iii. 22x
iv. 2x + 2
v. ![]()
i. 2x = 16
⇒ 2x = 24
⇒ x = 4 (∵ base is same)
ii. ![]()
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iii. 22x = 22× 4
⇒ 22x = 28
⇒ 22x = (2× 2× ……8 times)
⇒ 22x = 256
iv. 2x + 2 = 24 + 2
⇒ 2x + 2 = 26
⇒ 2x + 2 = 2× 2× 2× 2× 2× 2
⇒ 2x + 2 = 64
v. √2-x = √2-4


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