Express the following as a sum of consecutive odd numbers starting with 1
112
We know that any square can be expressed as the sum of consecutive odd numbers starting from 1.
n2 = 1 + 3 + 5 + … + (2n-1)
Therefore, 112 = 1 + 3 + 5 + … + (2 × 11-1)
= 1 + 3 + 5 + … + 21
= 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21
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