Find the smallest number by which each of the following number must be divided to obtain a perfect cube.
135
135
Prime Factorization:
⇒ 135 = 3 × 3 × 3 × 5
= 33 × 5
There is only one 5.
∴ 135 is not a perfect cube.
Since in factorization, 5 appear only one time, we should divide the number 135 by 5.
⇒ 135 ÷ 5 = 27
= 3 × 3 × 3
= 33 which is a perfect cube
∴ The smallest number by which the number 135 must be divided to obtain a perfect cube is 5.
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