Prove the following identities

Consider LHS,
LHS = ![]()
Multiplying and dividing with (1 – sinθ),
⇒
= ![]()
We know that (a + b) (a – b) = a2 – b2
⇒
= ![]()
We know that 1 – sin2θ = cos2θ.
⇒
= ![]()
= ![]()
= ![]()
We know that
= secθ and
= tanθ.
∴
= secθ + tanθ = RHS
Hence proved.
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