The angle of elevation of a hovering helicopter as seen from a point 45 m above a lake is 30° and the angle of depression of its reflection in the lake, as seen from the same point and at the same time, is 60°. Find the distance of the helicopter from the surface of the lake.

Given, ED = 45 m and DF = ?
Let EF = x, DF = h
⇒ DC = h (∵ height of reflection = height of object)
In a right triangle FAE,
We know,
![]()
![]()
![]()
AE = (h – 45) √3 ……… (1)
And, in right triangle ACE,
![]()
![]()
![]()
………(2)
Now, ∵BC = AD
⇒ equation (1) = equation (2)
![]()
⇒ 3(h – 45) = 45 + h
⇒ 3h – 135 = 45 + h
⇒ 2h = 45 + 135
⇒ 2h = 180
⇒ h = 90 m
∴ the distance of the helicopter from the surface of the lake is
90 m.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.