Q3 of 61 Page 204

Prove the following identities.

Consider LHS,


LHS =


We know that cot2θ = cosec2 – 1 and tan2θ = sec2θ – 1.


=


=


= 1 … (1)


Consider RHS,


RHS = (sinθcosθ) (tanθ + cotθ)


Expanding,


(sinθcosθ) (tanθ + cotθ) = sinθcosθtanθ + sinθcosθcotθ


We know that = tanθ and = cotθ.


(sinθcosθ) (tanθ + cotθ) = sinθcosθ() + sinθcosθ()


= sin2θ + cos2θ


We know that sin2θ + cos2θ = 1.


(sinθcosθ) (tanθ + cotθ) = 1 … (2)


From (1) and (2), LHS = RHS.


Hence proved.


More from this chapter

All 61 →