Prove the following identities.

Consider LHS,
LHS = ![]()
Multiplying and dividing by sinθ + cosθ + 1,
⇒
=
× ![]()
We know that (a + b) (a – b) = a2 – b2.
⇒
= ![]()
= ![]()
We know that 1 – cos2θ = sin2θ and sin2θ + cos2θ = 1.
= ![]()
= ![]()
= ![]()
= ![]()
We know that
= secθ and
= tanθ.
⇒
= secθ + tanθ
Multiplying and dividing by secθ – tanθ,
⇒
= secθ + tanθ × ![]()
= ![]()
We know that sec2 – tan2θ = 1.
∴
=
= RHS
Hence proved.
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