A simple pendulum of length 40 cm subtends 60° at the vertex in one full oscillation. What will be the shortest distance between the initial position and the final position of the bob? (between the extreme ends)

Given, OA = OC = length of pendulum = 40 cm, ∠AOC = 60°
In triangle OBC,
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= 30°
Here, OC = hypotenuse
AB = perpendicular
BC = base
We know,
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⇒ 40 = 2 BC
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⇒ BC = 20 cm
∴ length of AC = 2(BC)
= 2(20)
= 40 cm
∴ the shortest distance between the initial position and the final position of the bob = 40 cm
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