Two square pyramids have the same volume. The base edge of one is half that of the other. How many times the height of the second pyramid is the height of the first?
Let the volume of first pyramid be V1
Let the base edge of first pyramid be a1
Let the height of first pyramid be h1
Let the volume of second pyramid be V2
Let the area of first pyramid be a2
Let the height of first pyramid be h2
We know that,
Volume of a pyramid ![]()
Volume of a first pyramid![]()
Volume of a second pyramid![]()
Given: V1 = V2
….(1)
Given: ![]()
Substitute in (1)
![]()
⇒ h2 = 4h1
Couldn't generate an explanation.
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