What is the surface area of a cone of base diameter 30 centimetres and height 40 centimetres?
height of the cone = 40 cm
Base diameter = 30cm
Base radius ![]()
l = slant height
Applying Pythagoras theorem, we get:
l = √(h2 + rb2)
= √(402 + 152)
= √(1600 + 225) = √1825 cm
We know that, Curved surface area of cone = πrbl
Where rb = base radius and l = slant height
Curved surface area of cone = π× 15× √18255 = 640.8π cm2
Surface area of base = πrb2 = π × 152 = 225π cm2.
Total surface area = (640.8 + 225)π = 865.8π cm2
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