What is the surface area of a square pyramid of base perimeter 64 centimetres and volume 1280 cubic centimetres?
Base perimeter is given as 64 cm.
So base edge ![]()
Volume is given as 1280 cm3.
We know that,
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⇒ h = 15 cm
Let height of pyramid (h) = 15 cm
half of base edge = 8 cm
slant height = l
Applying Pythagoras theorem, we get:
l = √(152 + 82)
= √(225 + 64)
= √289
= 17 cm
Then area of one isosceles triangle![]()
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Area of four isosceles triangles = 4×136 = 544 cm2
Base area = 162 = 256 cm2.
Total surface area = (544 + 256) = 800 cm2
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