The slant height of a square pyramid is 25 centimetres and its surface area is 896 square centimetres. What is its volume?
Let the base edge be (2a) cm
Then area of one isosceles triangle![]()
.
Area of four isosceles triangles = 4×25a = 100a cm2.
Base area = (2a)2 = 4a2 cm2.
Total surface area = (100a + 4a2)cm2
Given total surface area = 896
∴ 100a + 4a2 = 896
⇒ a2 + 25a – 224 = 0
Using, ![]()
We get,


![]()
![]()
![]()
⇒ a = 7 or – 32
Since, base edge cannot be negative
∴ a = 7 cm

LG = Slant height = 25cm
HG = Half of base = 7cm
Apply Pythagoras theorem
LH = √(252 – 72)
= √(625 – 49)
= √576 = 24cm
Volume of a pyramid![]()
Volume of a pyramid![]()
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