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1. Euclids Algorithm and Real Numbers
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Q7 of 128 Page 18

Using (√7 + √3)(√7 — √3) = 4 and the fact that (√7 + √3) is irrational prove that √7 — √3 is irrational.

Given ( + )( — ) = 4 and ( + ) is irrational.


(multiplying numerator and denominator by )


=


(we know that (a – b) × (a + b) = (a2 – b2))


= =


Here, it is given that is irrational and we know that 4 is rational.


Therefore,


We know that rational divided by irrational is always irrational.


So, is irrational.


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Questions · 128
1. Euclids Algorithm and Real Numbers
1 2 3 4 5 6 1 1 1 2 3 4 1 1 1 1 2 2 2 2 3 3 3 4 4 4 4 4 5 6 7 8 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 2 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43 43
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