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1. Euclids Algorithm and Real Numbers
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Q37 of 128 Page 25

Find the smallest number which decreased by 15 is a multiple of 125 and 225.

The smallest number which is a multiple of 125 and 225 is the l.c.m. of them.

125 = 5 × 5 × 5


225 = 5 × 5 × 3 × 3


Therefore, l.c.m.(125, 225) = 5 × 5 × 5 × 3 × 3 = 1125


Now, we have to find the smallest number which is decreased by 15.


Therefore, the required number = 1125 + 15 = 1140


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Questions · 128
1. Euclids Algorithm and Real Numbers
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