1f n > 1, n⁴ + 4 is. n E N

(as a²–b² = (a + b)(a–b))

….. eq (1)

Now, n > 1

n – 1 > 0

Also,

Therefore, and are distinct positive integers.

So, we can say that

n–1 > 0

Similarly, n + 1 > 0

Therefore, are also distinct.

Thus, from eq(1) n⁴ + 4 has two distinct factors and 1 as a factor.

So, n⁴ + 4 is a composite number for n > 1.