In ΔABC, m∠B = 90, AC + BC = 25 and AB = 5, determine the value of sinA, cosA and tanA.

AC = 25 – BC
AC2 = AB2 + BC2 (by Pythagoras theorem)
(25–BC)2 = (5)2 + BC2
⇒ BC = 12
⇒ AC = 13 (by AC = 25 – BC)
By Pythagoras theorem
(25–BC)2 = 52 + BC2
⇒ BC = 12
⇒ AC = 13 and AB = 5
we know that
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, verify that tan2θ – sin2θ = tan2θ
cos2A – sin2A.