Prove the following by using trigonometric identities:
2sin2θ + 4sec2θ + 5cot2θ + 2cos2θ — 4tan2θ — 5cosec2θ = 1
L.H.S
2sin2θ + 4sec2θ + 5cot2θ + 2cos2θ — 4tan2θ — 5cosec2θ
= (2sin2θ + 2cos2θ) + ( 4sec2θ – 4tan2
) + (5cot2θ — 5cosec2θ)
= 2 + 4 – 5
= 1
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