Q29 of 104 Page 204

If 7θ and 2θ are measure of acute angles such that sin7θ = cos2θ then 2sin3θ — √3 tan3θ is ……….

sin7θ = cos2θ

∴ sin7θ = sin(90–2θ )


⇒ 9θ = 90


⇒ θ = 10


2sin3θ –√3tan3θ


put θ = 10


2sin3×20 – √3×tan (10× 3)


= 0

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