Prove the following:

sin48 sec42 + cos48 cosec42 = 2

cos(90–θ ) = sinθ

tan(90–θ ) = cotθ

sin(90–θ ) = cosθ

cot(90–θ ) = tanθ

cosec(90–θ ) = secθ

sec(90–θ) = cosecθ

L.H.S

sin48 sec42 + cos48 cosec42

= sin48sec(90–48) + cos48cosec(90–48)

= sin48cosec48 + cos48sec48

= 1 + 1

= 2 = R.H.S